Easy level problem 1

Finding the second lowest mark:

Given the students name and marks finding the  students name who has second lowest mark.

In case of more than one student with second lowest mark, arrange the names alphabetically.

 

Input format:

total number of students  n.

following  n*2 lines of names with marks.

Output format:

names arranged alphabetically.

Input:

7
Ramya
87.9
Abi
90.5
harry
99.5
Keerthi
60.5
preethi
60.5
nikita
60.5
Lavanya
50

 

Solution:

 

n=int(input())
main_list=[]
for i in range(0,n):
    sub_list=[]
    name=input().strip()
    mark=float(input())
    sub_list.append(mark)
    sub_list.append(name)
    main_list.append(sub_list)
main_list.sort()
lowest=main_list[0]

for i in main_list:
    if lowest[0] in i:
        main_list.remove(i)
        
second_lowest_mark=main_list[0][0]
second_lowest_name=main_list[0][1]
result=[]

for i in main_list:
    if second_lowest_mark in i:
        result.append(i[1])
result.sort()
print(result)